Hex Online Teks Decoder

I'm using the snmp-library (https://github.com/soniah/gosnmp) for golang and after SNMP-request it give me the string with some text, example: "120switch type.....bla bla some words or digits" or hex-string (MAC-adress), example: "48 56 BE A0 ..."How can I separate this to convert in string and write to postgreSQL databaseAnd how can i write HEX-string correctly

    func snmp_request(current_ip string, current_oid string) string {           g.Default.Target = current_ip        oids := []string{current_oid}        result, _ := g.Default.Get(oids)        var a int        for _, variable := range result.Variables {            switch variable.Type {            case g.OctetString:  // problem here!!!                fmt.Printf("string: %s\n", string(variable.Value. ([]byte)))                return string(variable.Value.([]byte))            default:                fmt.Printf("number: %d\n", g.ToBigInt(variable.Value))                var res string                res = strconv.Itoa(a)                return res            }        }        return " "    }       func main(){        result := snmp_request("11.11.11.11", "1.2.3.4.5.6.7")    }

if I recieve data = string no problem, if i recieve HEX-string the result will be like this: H�-�S

oid = Enterprise 10port switch Hardare777.company => output = Enterprise 10port switch Hardare777.company

oid = 10 22 B0 A1 2F FF => output = H�-�S

EXAMPLE OF HEX RESULT FROM GOLANG-LIBRARY:

0: oid: .1.3.6.1.4.1.25972.102.0.1.55.1.6.0 string: H�-�S

in console snmp-request to same OID gives this result:

serg@serg-CITI-E201:~$ snmpwalk -v2c -c public 10.19.1.232 1.3.6.1.4.1.25972.102.0.1.55.1.6.0iso.3.6.1.4.1.25972.102.0.1.55.1.6.0 = Hex-STRING: 48 BE 2D 19 A0 53 

I have found out a problem with python 3.6.7 when I tried to stringfy a hexadecimal value. The original hexadecimal number in the string is wrongly converted into an acsii letter Ë. Is there any way for solving this?

>>>  '\xcb\x85\x04\x08''Ë\x85\x04\x08'

I'm Using Python 3.7.3 on Centos RHEL Fedora.

Taking a CSV File which contains lines of byte data. I am able to decode those strings without a problem, except where the line has a "Hex" character.

Example String from the file:

b'12010000,NY0400001111121242221121,1,001,Get Apple \x42 Device Soon,2011-04-10 00:01:21\r\n'

I would like to have the \x42 data converted to its ascii value, OR to remove it completely.

I have tried decoding it using s.decode(). But that produces an error of "UnicodeDecodeError: 'utf-8' codec can't decode byte 0x96 in position 48: invalid start byte"

I have tried to read the string in one character at a time, but since it is still byte, I don't get back a meaningful data point.

Probably missing something basic, but I haven't been able to figure this out.Any ideas?

Desired Output:

b'12010000,NY0400001111121242221121,1,001,Get Apple B Device Soon,2011-04-10 00:01:21\r\n'orb'12010000,NY0400001111121242221121,1,001,Get Apple  Device Soon,2011-04-10 00:01:21\r\n'

EDIT:Other coders have stated they are able to read this line. So I thought I would try a different line, and display step by step the path:

>>> read_file=open(old_NME, 'rb')>>> lines=read_file.readlines()>>> lines[10]b'2806817,DE39649173950492739481,9,999,Get Data \x96 Input accepted,2011-09-10 07:37:11\r\n'>>> s = b'2806817,DE39649173950492739481,9,999,Get Data \x96 Input accepted,2011-09-10 07:37:11\r\n'>>> s == lines[10]True>>> s.decode()Traceback (most recent call last):  File "<stdin>", line 1, in <module>UnicodeDecodeError: 'utf-8' codec can't decode byte 0x96 in position 48: invalid start byte>>>

I am trying to store a hexadecimal string value : ex "3958ABBFEC23BD40" to uint64 which would like this:

fmt.Println(myuint64)$ 0x3958ABBFEC23BD40

I have tried using encoding/hex, or strconv to int, etc... I couldn't find any solution.

file, err := os.Open("myfile")if err != nil {    fmt.Println("erreur",err)}b := bufio.NewReader(file)a,_ := b.Peek(16)d, err := strconv.ParseUint(string(a), 0, 64)if err != nil {    panic(err)}fmt.Printf("%d\n%s\n", d,string(a))

Obviously I am not getting the result expected :

$ 4132241498901298496fcb9ca7c63ec7c5d

expected :

$ 0xfcb9ca7c63ec7c5d

using the following code, I have retrieve the good uint, but I can't convert it to hexa, unless by using strconv, but I don't wish to work with a string.

v := *(*[8]byte)(unsafe.Pointer(&d))var final []byte = v[:]var n uint64buf := bytes.NewBuffer(final)binary.Read(buf, binary.LittleEndian, &n)fmt.Println(strconv.FormatUint(n, 16))

result : $ fcb9ca7c63ec7c5d but as string, and expected $ fcb9ca7c63ec7c5d type of uint64...

I hope this isn't too much of a stupid question, I have looked on 5 different pages of Google results but haven't been able to find anything on this.

What I need to do is convert a string that contains all Hex characters into ASCII for example

String fileName = 75546f7272656e745c436f6d706c657465645c6e667375635f6f73745f62795f6d757374616e675c50656e64756c756d2d392c303030204d696c65732e6d7033006d7033006d7033004472756d202620426173730050656e64756c756d00496e2053696c69636f00496e2053696c69636f2a3b2a0050656e64756c756d0050656e64756c756d496e2053696c69636f303038004472756d2026204261737350656e64756c756d496e2053696c69636f30303800392c303030204d696c6573203c4d757374616e673e50656e64756c756d496e2053696c69636f3030380050656e64756c756d50656e64756c756d496e2053696c69636f303038004d50330000

Every way I have seen makes it seems like you have to put it into an array first. Is there no way to loop through each two and convert them?