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I'm trying to convert a hex as string:
string hex = "0x123";to a hex as int:
int hex = 0x123;
In various languages, you can embed hex values in a string literal by using the \x escape sequence:
How can I do the same thing in Lua 5.1?
A value like
0x05 has to be given to a function as a string without the 0x at the beginning so
If I use
str(hex(0x0F))[2:4] I only get
f. It is crucial that the missing
0 is still present in my application.
How can i do that?
I have a long string, and I would like to remove a specific hexadecimal character from it.
NSString * myString = @"longlongstringwithcharacters\"ofallsorts\"";
The hex character I am after is 08, that corresponds to backspace. How can I use code like the following to substitute it? I have no idea on how to represent 08 in a string:
NSString *stringWithoutSpaces = [myString stringByReplacingOccurrencesOfString:@" " withString:@""];
I will try to clarify a bit more what I am trying to do..
I am trying to remove all occurrences of a character that corresponds to 08 hex from the string that I receive as payload.
The payload is in a string format and I found out the character by using Xcode debugger and view the hex codes of the string as there was an invalid character when trying to covert the NSData corresponding to the string to a NSDictionary.
I am not sure how to phrase the problem correctly..
I need to send a message in the following format:
"\x9F\x02\x06\x00\x00\x00\x07\x00\x00\x9F\x03\x06\x00\x00\x00\x00\x00\x00\x9A\x03\x15\x04\x24" (Hexadecimal bytes)
The last three Hexadecimal bytes represent a date.
I need to retrieve the date from the system (Payment terminal) every time I want to send this message, the date given by the system have a string format:
The problem is that I need to format this date into Hexadecimal Bytes and then concatenate the result with the the rest of the message!
Can any one help me to resolve this problematic ?