On-line Cadeia Reversa

I'm writing the logic for reverse word by word in string javascript.

But I'm thinking my code is more lengthy so, I'm looking for good answer.

Ex :- I/p- Hi how are you // o/p- iH woh era uoy

<script>  function ReverseString(val) {    var op = "",      iCount = -1;    for (let i = 0; i <= val.length; i++) {      if (val[i] != " " && i != val.length)        continue;      for (let j = i - 1; j > iCount; j--)        op += val[j];      if (i != val.length)        op += " ";      iCount = i;    }    return op;  }  console.log(ReverseString("Hi how are you"));</script>

Suppose you have a String and a CAPITAL letter in that indicates ending of a word. For example, if you have wElovEcakE where E, E and K indicates end of the words wE, lovE and cakE respectively. You need to reverse each word (as you know where it ends). Don’t reverse the String as a whole. To illustrate, if we give wElovEcakE as input output should be EwEvolEkac. See wE became Ew, lovE became Evol and so on....

And the way i tried to approach with ..

import java.util.Scanner;public class Alternative {    public static void main(String[]args) {        Scanner robo=new Scanner (System.in);        System.out.println("Enter  a word ");        String word=robo.nextLine();        char[] array=word.toCharArray();        for(int i =0;i<array.length;i++){            int count =0;            for(int j=0;j<=("EMPTY");j++)  // here i am trying to operate a loop where it will work up to the Capital letter.                count ++;             } //Code incomplete        }    }}

Above i have mentioned "EMPTY" in the condition part ... i want to operate a loop where my loop will work up to the capital letter , then i will count all the letter that i have counted up to capital letter then last step will be like i will make another loop where i will reverse all the letter where condition for the loop will <=count ;Example:lovE (counted 4 letters i will reverse four times back).

Can you guys help me to write the condition at "EMPTY" part if you think that my approach is correct ..Can you guys help me to solve the problem in any other way ?

I'm new to C and I'm attempting to perform a modification to a string that I have (I'm attempting to reverse it), but I'm unsure why the program doesn't run as intended (displays no output).

void reverse(char *rTarget);int main(){    char memes[] = "memes";    reverse(memes);    printf("%s", memes);}void reverse(char *rTarget){    char swap;    int length = (int) strlen(rTarget);    for (int i = 0; i < length / 2; i++)    {        swap = rTarget[i];        rTarget[i] = rTarget[length - i];        rTarget[length - i] = swap;    }}

So I have an assignment where I need to reverse a string that is inputted using a loop instruction (without using push or pop). I have managed to get the program to rewrite the string character by character, but I am not sure how to reverse it. I believe that i need to index the last character of the string and reprint them in the loop, but I am not sure how to go about that. Not asking anyone to write the code for me, but any help would be appreciated.

INCLUDE Irvine32.inc.data    promptQuestion BYTE "Enter a phrase you would like to reverse!",0dh,0ah,0    reverseWord  BYTE 127 DUP(?)main PROC    call Clrscr    mov edx, OFFSET promptQuestion ;prompt question    call WriteString    mov edx, OFFSET reverseWord     mov ecx, 20                 ;set char limit    Call ReadString             ;take user input    mov ebx, 0    mov edx, OFFSET reverseWord    mov ecx, eax                ;prepare counterReverseOrder:    dec ebx    mov al, reverseWord[ebx]    mov reverseWord, al    call WriteChar    loop reverseOrder    exitmain ENDPEND main

How do you reverse a string in place (or in-place) in JavaScript when passed to a function with a return statement? All without using the built-in functions (.reverse(), .charAt(), etc.) ?